ARITHMETICS
OF EXPONENTS
Objectives:
Recall 1: Rules for
exponents.
These rules tell us how to
multiply and divide powers
of a number.
3^2 means
3*3,
3^5 means 3*3*3*3*3,
7^4 means 7*7*7*7,
and, more generally,
x^5 means x*x*x*x*x.
When we write 7^4, we call 4 the exponent
and
7 the base.
The exponent is the
number that tells you how many 7's
to multiply together to make
7^4.
In general, the number x^n has an exponent n and base x.
This means that we must multiply x by itself n times in order to have the same
number that x^n represents. Clearly, this only makes sense if n is a positive
number.
You may have forgotten the basic rules for multiplying exponents and raising exponents to powers. Here are some general rules.
1. x^m*x^n = x^(m+n),
2. (x^m)^n = x^(m*n).
It is easy to convince yourself that the two rules above are true. Take a few sample numbers -- let x = 3, m = 2 and n = 5. The question is whether or not the equalities
3^2*3^5 = 3^(2+5)
and
(3^2)^5 = 3^(2*5)
hold. The validity of these equations does not prove the general equations 1 and 2, but it does make them more believable.
Notice that the first equality may be written as
(3*3)*(3*3*3*3*3) =
3^7,
or as
3*3*3*3*3*3*3
= 3^7.
This last equality is true, by definition of 3^7.
What about the equality (3^2)^5 = 3^(2*5) ? Convince yourself that it is true.
Recall 2: Zero and negative exponents.
3. x^0 =
1
and that
4. ![]()
We shall not go into the reasons for this. Just think of x^(-n) as short hand notation for 1/(x^n) . and x^(m-n) as short hand for (x^m)/(x^n).
Recall 3: Products and quotients
of powers.
What happens when you
take the product or
quotient of a number raised to a
power?
It is easy to see that the equalities below hold.
(3^4)*(5^4) = (3*5)^4,
and, more generally,
5. (x^n)*(y^n) = (x*y)^n.
Also
![]()
and, more generally,
6. .![]()
Examples
Example 1. Expand x^8.
Solution: The symbol x^8 means multiply x by itself 8 times. You get
x^8=x*x*x*x*x*x*x*x
The
symbol -x^8 generally means -(x^8), or
-x*x*x*x*x*x*x*x.
However,
the symbol
(-x)^8 means (-x)*(-x)*(-x)*(-x)*(-x)*(-x)*(-x)*(-x),
which, in turn means
x*x*x*x*x*x*x*x, because (-x)*(-x) = x*x.
Example 2. Find other ways of writing (1/x)^5.
Solution: The symbol (1/x)^5.
means
multiply 1/x by itself 5 times. You get
(1/x)^5= (1/x)*(1/x)*(1/x)*(1/x)*(1/x).
You may also use rule 6 to get (1/x)^5=(1^5)/(x^5) , which may be written as 1/(x^5).
You may now use rule 4 to get 1/(x^5)= x^(-5).
Example 3
(a) (x^7)*x = x^8.
(b) (2*x)^3*(2*x)^5 = (2*x)^(3+5) = (2*x)^8.
Note
1. x^2 + x^3 cannot be written in any other way, since it is a sum of two powers, not a product.
2. 2^3*5^4 cannot be simplified, because the bases are different.
Example 4

Simplify each of the following expressions:
1. 5*x^2*x^3
2.
(5*x)^3*3*x^2
3
(9*x*y*z^3)^2
4
(5*x^3*3*x^2)*(3*x^4)
5
(5*x^3*3*y^2)*(3*x^4)
6
(3*a^3)^3
7
[(3*x)^5]/[(3*x)^(-5)]
8 -![]()
9 ![]()
10. Write
![]()
using only positive exponents.
11 Write
![]()
using only positive
exponents.
12
Simplify
![]()
13
Write [(x^(-1)*y^(-1)]^(-1) using only
positive
exponents.
14 Write
[(x^(-1)+y^(-1)]^(-1) using only
positive
exponents.
15 Simplify
.(x^2+x^0)*(1+x^2)^(-1).
16
Simplify
.