SIMPLIFYING
EXPRESSIONS
Objectives: To recall how to simplify expressions using associative, commutative and distributive rules of arithmetic.
Recall 1: Commutative laws for addition
and
multiplication.
These laws
tell us that the order in which
we add or multiply numbers is
not important.
Adding 5 and 6 is the same as adding 6 and 5. The order in which we add any two numbers is not important, as the equalities below illustrate.
5 +
6 = 6 + 5,
3 + 7 = 7 + 3,
x + y = y + x.
The law that permits us to flip numbers around an addition sign is called the commutative law for addition. It holds for any real numbers x and y, fractions or decimals, as well as for integers. In other words
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or
2.343 + 5.437 = 5.437 + 2.343.
Multiplying 5 and 6 is the same as multiplying 6 and 5. The order in which we multiply any two numbers is not important, For example:
5 *6 = 6 *
5,
3 * 7 = 7 * 3,
and, more generally,
x * y = y * x.
The law that permits us to flip numbers around a multiplication sign is called the commutative law for multiplication. It holds for any real numbers x and y, fractions or decimals, as well as for integers. In other words
2.343 * 5.437 = 5.437 * 2.343.
Recall
2: Associative laws for addition
and
multiplication.
These laws
tell us that we may move parentheses
around.
Adding 5 and 6, then adding 7, is the same as adding 5, then adding the sum of 6 and 7. This works for any three numbers, as the equalities below illustrate.
(5 + 6) + 7 = 5 + (6
+ 7),
(3 + 7) + 9 = 3 + (7 + 9),
or, more generally,
(x + y) + z = x + (y + z)
The law that permits us to move parentheses around in this manner is called the associative law for addition. It holds for x and y and z fractions or decimals, as well as for integers. In other words
(2.343 + 5.437) + 3.546 = 2.343+ (5.437 + 3.546)
Multiplying 5 and 6, then multiplying the result by 7, is the same as multiplying 5 by the product of 6 and 7. Moreover:
(5 * 6) * 7= 5 * (6 *
7),
(3 * 7) * 9 = 3 * (7 * 9),
and, more generally,
(x * y) * z = x * (y * z)
This law is called the associative law for multiplication. It holds for x and y and z fractions or decimals. In other words
(2.343 * 5.437) * 3.546 = 2.343.* (5.437 * 3.546).
Recall 3:
Distributive laws for multiplication
over
addition.
This law will be
very useful in simplifying
complicated algebraic
expressions.
Multiply 5 and (6 + 7). You get 65. Now add 5 x 6 to 5 x 7. You again get 65. In other words
5 * (6 + 7) = 5 * 6 + 5 * 7
Again, we should notice that the 5, 6 and 7 may be replaced by any three numbers. For example, for 3, 7 and 9 we have:
3 * (7 + 9) = 3 *7 + 3 * 9
More generally, we find that
x * (y + z) = x* y + x * z
The law that permits us to write x * (y + z) as x * y + x * z is called the distributive law for multiplication over addition. It holds for x, y, and z fractions or decimals. In other words
2.343 *( 5.437 + 3.546) = 2.343.* 5.437 + 2.343 * 3.546
The examples below demonstrate how the three laws just described (the commutative, associative and distributive laws) allow us to simplify complicated expressions.
Examples
Example 1. Simplify the expression 3*(5 + 3*(x + 9) + y).
Solution: Work with the middle term inside the
parentheses
first, 3*(x + 9). The distributive law says that this term
must be the
same as
3*x + 3*9,
or
3*x + 27.
Replacing 3*(x + 9) by 3*x + 27, we find that the expression
may
be written as
3*(5 + 3*x + 27 +
y).
The commutative law says that we may flip the 3*x and the 27, to get an expression that looks like:
3*(5 + 27 + 3*x + y).
The associative law allows us to rewrite the expression as
3*((5 + 27) + 3*x + y),
or as
3*(32 + 3*x + y).
Finally, we may use the distributive law once again to distribute the 3 over the addition to get the final simplified form
3*32 + 3*3 x +
3*y,
or
96 + 9*x +
3*y.
Note
The laws discussed above work
equally as well for negative
numbers, though we sometimes must interpret
the results more carefully.
For example,
(3 - 5) is different from (5 - 3).
However, (x - y) means x + (-y); so, if the first number is 3 and the second is -5 then indeed the commutative law for addition does work and
3 + (-5) = (-5)+3.
Example 2. Simplify the expression 3 x ((x - y) + 5*(x + y)).
Solution: Always work with the
innermost
parentheses first. In this case we work
with
(x - y) + 5*(x + y).
It simplifies to become
(x -
y) + 5*x + 5*y, (by the distributive
law)
then
x - y + 5*x + 5*y, (by
the associative law)
then
x + 5*x + (-y) + 5*y, (by the
commutative
law)
then
(x + 5*x) + (-y + 5*y) (by the
associative
law)
and finally
6*x + 4*y (by the associative law)
So, the expression inside the innermost parentheses is 6*x + 4*y. Recall that the original expression was 3*x*((x - y) + 5*(x + y)), which may now be represented as
3*x*(6*x +
4*y)
This simplifies to
(3*x)*(6*x) + (3*x)*(4*y) (by the
distributive
law)
(3*6)*(x*x) + (3*4)*(x*y) (by the associative law)
18*x^2 + 12*x*y (by multiplication rules)
Example
3 Show that
.
Solution: (x + y)^2 means (x + y)*(x + y). Use the distributive law once to get
(x + y)*x + (x + y)*y,
the commutative law for multiplication to get
x*(x + y) + y*(x + y),
and the distributive law again in each of the two terms to get
x*x + x*y + y*x +
y*y,
or
x^2 + 2*x*y +
y^2.
Example
4 Show that ![]()
Solution: Let y = 1 in Example 3.
Warning 1: Always check your answers. In algebra, it is usually simple to check an answer. The expression will become a real number, if you declare the unknowns to be specific real numbers. So, pick values for the unknowns, and you should get the same unknown for the original expression as you do for the simplified expression. The first example demonstrated that 3*(5 + 3*(x + 9) + y) can be rewritten as 96 + 9*x + 3*y. This means that
(equality 1) 3*(5 + 3*(x + 9) + y).= 96 + 9*x + 3*y.
If this last equality is true, then it must be true for any numbers that x and y stand for. In particular, it must be true for x = 1 and y = 1.
If we let x = 1 and y = 1, then this equation
becomes
3*(5 + 3*(1 + 9) + 1).= 96 + 9*1 +
3*1.
Since both the left and right sides are equal to 108, the equality 1 stands a good chance of being correct.
Note: Checking, by substituting simple numbers for x and y, does not guarantee that Equality 5.1 is correct, as it may have been a coincidence that the two expressions were equal for those specific choices for x and y; however, such simple choices of x and y usually would determine an error, had one occurred. So, it is important to get into the habit of checking for errors.
Warning 2: Your biggest frustrations will occur when you work out an exercise with haste and carelessness. It does not take many mistakes to shake your self confidence; that is a human condition. Studies show that most students find math difficult because of a lack of self confidence rather than a lack of ability. So take your time and check your results.
You are now ready to
carefully do the workout exercises.
EXERCISES (Workout
5)
Evaluate or simplify each of the following expressions:
1. 2*(5 + 4) - 3*(2 +
4)
2. 3*(4*(5 + 3) + (2 +
3))
3. 2*(2*(2 + 2) +
2*(2 + 2))
4. 2*(x + 4) -
3*(x + 4)
5. 3*(4*(x + 3) +
(2 + x))
6. 2*(2*(x + 2) +
2*(x + 2))
7. 2*(5 - 4) -
3*(2 - 4)
8. -3*(4*(-5 + 3)
+
(2 - 3))
9. 3*(x*(5 - 3) + (x - 3))
10. 2*(x*(2 + x) + 2*(x +
2))
11. 2*(5 + z) - 3*(2 +
z)
12. x*(5 - 4) - x*(2 +
4)
13. y*(4*(x + 3) + (y +
x))
14. -3*y*(x - 3) - (-x*(y + 4))
15. -4*x*(z +
y)
+ (x*(x - y))
16. -4*a*((c +
b) + a*(a - b))
17. 3*((h +
k
- m) + 3*(h - k))
18. 3*((x^2 - 2*y + z) - (x - x*y))
Checking for
common
errors:
1. Suppose that you are given the expression x*(x + 2) to simplify, and that you used the distributive law incorrectly to answer x^2 + 2. (It is easy to see how this typical mistake can happen; you may forget to multiply the 2 by the x.) Next, suppose that you wish to check your result, which means checking that
Equality 5.2 x*(x + 2) = x^2 + 2.
You choose to check the equality at x = 1. So you check that
1*(1 + 2) = 1^2 + 2.
You calculate that the right side and the left side are both equal to 3. You may feel that your answer is correct, but it isn't. If you want a better test for the accuracy of your answer, it is wise to plug in another simple value for x, say x = 0. Now, if you evaluate both sides of Equality 5.2 at x = 0, you find that the left side is 0, while the right is 2. Therefore, your answer has failed the test.
The lesson to be learned is that if you are not sure of an answer, check it at at least one value of each of the unknowns. It is generally unlikely that the beginning expression and the answer expression will both accidentally have the same value when evaluated at a single value of each of the unknowns; however, it is even more unlikely that checking at two values of each of the unknowns will accidentally give the same value.
2. A majority of the
common errors that you will encounter
in performing the exercises of
the Workout 5 will be careless ones.
Here are several that you
may have made in the last workout.
Can you find the errors in
the solutions to Workout 5, Exercises
below? (Note:
these are samples from students who volunteered
to work through the
first draft of Day Algebra Workout.)
Incorrect solution
to Exercise
6
2*(2*(x + 2) + 2*(x + 2))
2*(2*x + 4 + 2*x + 2)
2*(6 +
4*x)
12 + 8*x
Incorrect
solution
to Exercise 9
3*(x*(5 - 3) + (x - 3))
3*(5*x - 9 + x -
3)
3*(6*x -12)
18*x -
36
Incorrect solution
to
Exercise 14
-3*y*(x - 3) - (-x*(y + 4))
-3*y*(x - 3) - (-x*y - 4*x)
-3*y*(x - 3 + x*y + 4*x)
-3*x*y - 3*y -
3*x*y2 - 12*x*y
- 15*x*y - 3*y -
3*x*y2.
Incorrect solution
to Exercise 18
Here is a typical
error, 3*((x^2 - 2*y + z) - (x
- x*y))
where
the student 3*(x^2 - 2*y + z -
x + x*y)
carelessly copied 3*x - 6*y + 6 - 3*x +
3*x*y.
what she had
written.
There are two errors in this last
solution -- one is the
result of not writing clearly enough to distinguish
between a z and a 2.
ANSWERS
(Workout
5)
1. 0 10. 2*x^2 + 8*x +
8
2.
111 11. 4 -
z
3.
32 12.
-5*x
4. -x -
4 13.
5*x*y + 12*y + y^2
5. 15*x +
42 14. -2*x*y + 9*y + 4*x
6. 8*x + 16 15. x^2 - 4*x*z -
5*x*y
7.
8 16.
4*a^2*b - 4*a*c - 4*a*b - 4*a^3
8. 27 17. 12*h - 6*k -
3*m
9. 9*x -
9 18.
3*x^2 - 6*y + 3*z - 3*x +
3*x*y